23-(3x+3)=3(x+2)+x

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Solution for 23-(3x+3)=3(x+2)+x equation: 



23-(3x+3)=3(x+2)+x

We move all terms to the left:

23-(3x+3)-(3(x+2)+x)=0

We get rid of parentheses

-3x-(3(x+2)+x)-3+23=0



We calculate terms in parentheses: -(3(x+2)+x), so:

3(x+2)+x

We add all the numbers together, and all the variables

x+3(x+2)

We multiply parentheses

x+3x+6

We add all the numbers together, and all the variables

4x+6

Back to the equation:

-(4x+6)



We add all the numbers together, and all the variables

-3x-(4x+6)+20=0

We get rid of parentheses

-3x-4x-6+20=0

We add all the numbers together, and all the variables

-7x+14=0

We move all terms containing x to the left, all other terms to the right

-7x=-14

x=-14/-7

x=+2

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