23-(x+5)=4(x-2)

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Solution for 23-(x+5)=4(x-2) equation:



23-(x+5)=4(x-2)
We move all terms to the left:
23-(x+5)-(4(x-2))=0
We get rid of parentheses
-x-(4(x-2))-5+23=0
We calculate terms in parentheses: -(4(x-2)), so:
4(x-2)
We multiply parentheses
4x-8
Back to the equation:
-(4x-8)
We add all the numbers together, and all the variables
-1x-(4x-8)+18=0
We get rid of parentheses
-1x-4x+8+18=0
We add all the numbers together, and all the variables
-5x+26=0
We move all terms containing x to the left, all other terms to the right
-5x=-26
x=-26/-5
x=5+1/5

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