23-(x+5)=4(x-2)

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Solution for 23-(x+5)=4(x-2) equation: 



23-(x+5)=4(x-2)

We move all terms to the left:

23-(x+5)-(4(x-2))=0

We get rid of parentheses

-x-(4(x-2))-5+23=0



We calculate terms in parentheses: -(4(x-2)), so:

4(x-2)

We multiply parentheses

4x-8

Back to the equation:

-(4x-8)



We add all the numbers together, and all the variables

-1x-(4x-8)+18=0

We get rid of parentheses

-1x-4x+8+18=0

We add all the numbers together, and all the variables

-5x+26=0

We move all terms containing x to the left, all other terms to the right

-5x=-26

x=-26/-5

x=5+1/5

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