23-3/7y=2/7y-42

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Solution for 23-3/7y=2/7y-42 equation: 



23-3/7y=2/7y-42

We move all terms to the left:

23-3/7y-(2/7y-42)=0



Domain of the equation: 7y!=0

y!=0/7

y!=0

y∈R





Domain of the equation: 7y-42)!=0

y∈R



We get rid of parentheses

-3/7y-2/7y+42+23=0

We multiply all the terms by the denominator


42*7y+23*7y-3-2=0

We add all the numbers together, and all the variables

42*7y+23*7y-5=0

Wy multiply elements

294y+161y-5=0

We add all the numbers together, and all the variables

455y-5=0

We move all terms containing y to the left, all other terms to the right

455y=5

y=5/455

y=1/91

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