23-5(3-y)=-4(y-2)+9y

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Solution for 23-5(3-y)=-4(y-2)+9y equation: 



23-5(3-y)=-4(y-2)+9y

We move all terms to the left:

23-5(3-y)-(-4(y-2)+9y)=0

We add all the numbers together, and all the variables

-5(-1y+3)-(-4(y-2)+9y)+23=0

We multiply parentheses

5y-(-4(y-2)+9y)-15+23=0



We calculate terms in parentheses: -(-4(y-2)+9y), so:

-4(y-2)+9y

We add all the numbers together, and all the variables

9y-4(y-2)

We multiply parentheses

9y-4y+8

We add all the numbers together, and all the variables

5y+8

Back to the equation:

-(5y+8)



We add all the numbers together, and all the variables

5y-(5y+8)+8=0

We get rid of parentheses

5y-5y-8+8=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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