23/3x+3.42=4

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Solution for 23/3x+3.42=4 equation: 



23/3x+3.42=4

We move all terms to the left:

23/3x+3.42-(4)=0



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



We add all the numbers together, and all the variables

23/3x-0.58=0

We multiply all the terms by the denominator


-(0.58)*3x+23=0

We multiply parentheses

-1.74x+23=0

We move all terms containing x to the left, all other terms to the right

-1.74x=-23

x=-23/-1.74

x=13+0.38/1.74

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