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2330=(x-9)x
We move all terms to the left:
2330-((x-9)x)=0
We calculate terms in parentheses: -((x-9)x), so:We get rid of parentheses
(x-9)x
We multiply parentheses
x^2-9x
Back to the equation:
-(x^2-9x)
-x^2+9x+2330=0
We add all the numbers together, and all the variables
-1x^2+9x+2330=0
a = -1; b = 9; c = +2330;
Δ = b2-4ac
Δ = 92-4·(-1)·2330
Δ = 9401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{9401}}{2*-1}=\frac{-9-\sqrt{9401}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{9401}}{2*-1}=\frac{-9+\sqrt{9401}}{-2} $
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