234(21b-1)=(84+1b)789

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Solution for 234(21b-1)=(84+1b)789 equation: 



234(21b-1)=(84+1b)789

We move all terms to the left:

234(21b-1)-((84+1b)789)=0

We add all the numbers together, and all the variables

234(21b-1)-((b+84)789)=0

We multiply parentheses

4914b-((b+84)789)-234=0



We calculate terms in parentheses: -((b+84)789), so:

(b+84)789

We multiply parentheses

789b+66276

Back to the equation:

-(789b+66276)



We get rid of parentheses

4914b-789b-66276-234=0

We add all the numbers together, and all the variables

4125b-66510=0

We move all terms containing b to the left, all other terms to the right

4125b=66510

b=66510/4125

b=16+34/275

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