23=1/2((3x-1)+(8x+3)

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Solution for 23=1/2((3x-1)+(8x+3) equation: 



23=1/2((3x-1)+(8x+3)

We move all terms to the left:

23-(1/2((3x-1)+(8x+3))=0



Domain of the equation: 2((3x-1)+(8x+3))+23!=0

We move all terms containing x to the left, all other terms to the right

2((3x-1)+(8x+3))!=-23

x∈R



We multiply all the terms by the denominator


-(1=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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