23=2c-6(-3+6c)-12

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Solution for 23=2c-6(-3+6c)-12 equation: 



23=2c-6(-3+6c)-12

We move all terms to the left:

23-(2c-6(-3+6c)-12)=0

We add all the numbers together, and all the variables

-(2c-6(6c-3)-12)+23=0



We calculate terms in parentheses: -(2c-6(6c-3)-12), so:

2c-6(6c-3)-12

We multiply parentheses

2c-36c+18-12

We add all the numbers together, and all the variables

-34c+6

Back to the equation:

-(-34c+6)



We get rid of parentheses

34c-6+23=0

We add all the numbers together, and all the variables

34c+17=0

We move all terms containing c to the left, all other terms to the right

34c=-17

c=-17/34

c=-1/2

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