23=3(y-3)-7y

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Solution for 23=3(y-3)-7y equation: 



23=3(y-3)-7y

We move all terms to the left:

23-(3(y-3)-7y)=0



We calculate terms in parentheses: -(3(y-3)-7y), so:

3(y-3)-7y

We add all the numbers together, and all the variables

-7y+3(y-3)

We multiply parentheses

-7y+3y-9

We add all the numbers together, and all the variables

-4y-9

Back to the equation:

-(-4y-9)



We get rid of parentheses

4y+9+23=0

We add all the numbers together, and all the variables

4y+32=0

We move all terms containing y to the left, all other terms to the right

4y=-32

y=-32/4

y=-8

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