23=5(-2+2y)+4y

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Solution for 23=5(-2+2y)+4y equation: 



23=5(-2+2y)+4y

We move all terms to the left:

23-(5(-2+2y)+4y)=0

We add all the numbers together, and all the variables

-(5(2y-2)+4y)+23=0



We calculate terms in parentheses: -(5(2y-2)+4y), so:

5(2y-2)+4y

We add all the numbers together, and all the variables

4y+5(2y-2)

We multiply parentheses

4y+10y-10

We add all the numbers together, and all the variables

14y-10

Back to the equation:

-(14y-10)



We get rid of parentheses

-14y+10+23=0

We add all the numbers together, and all the variables

-14y+33=0

We move all terms containing y to the left, all other terms to the right

-14y=-33

y=-33/-14

y=2+5/14

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