23=x+2x+(2+4x)

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Solution for 23=x+2x+(2+4x) equation: 



23=x+2x+(2+4x)

We move all terms to the left:

23-(x+2x+(2+4x))=0

We add all the numbers together, and all the variables

-(x+2x+(4x+2))+23=0



We calculate terms in parentheses: -(x+2x+(4x+2)), so:

x+2x+(4x+2)

We add all the numbers together, and all the variables

3x+(4x+2)

We get rid of parentheses

3x+4x+2

We add all the numbers together, and all the variables

7x+2

Back to the equation:

-(7x+2)



We get rid of parentheses

-7x-2+23=0

We add all the numbers together, and all the variables

-7x+21=0

We move all terms containing x to the left, all other terms to the right

-7x=-21

x=-21/-7

x=+3

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