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23=x-9/x=14
We move all terms to the left:
23-(x-9/x)=0
Domain of the equation: x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-(+x-9/x)+23=0
We get rid of parentheses
-x+9/x+23=0
We multiply all the terms by the denominator
-x*x+23*x+9=0
We add all the numbers together, and all the variables
23x-x*x+9=0
Wy multiply elements
-1x^2+23x+9=0
a = -1; b = 23; c = +9;
Δ = b2-4ac
Δ = 232-4·(-1)·9
Δ = 565
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-\sqrt{565}}{2*-1}=\frac{-23-\sqrt{565}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+\sqrt{565}}{2*-1}=\frac{-23+\sqrt{565}}{-2} $
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