23p=5p2+24

Solution for 23p=5p2+24 equation:

23p=5p^2+24

We move all terms to the left:

23p-(5p^2+24)=0

We get rid of parentheses

-5p^2+23p-24=0

a = -5; b = 23; c = -24;
Δ = b2-4ac
Δ = 232-4·(-5)·(-24)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-7}{2*-5}=\frac{-30}{-10}
=+3
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+7}{2*-5}=\frac{-16}{-10}
=1+3/5
$