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23x+14=11/6x-13
We move all terms to the left:
23x+14-(11/6x-13)=0
Domain of the equation: 6x-13)!=0We get rid of parentheses
x∈R
23x-11/6x+13+14=0
We multiply all the terms by the denominator
23x*6x+13*6x+14*6x-11=0
Wy multiply elements
138x^2+78x+84x-11=0
We add all the numbers together, and all the variables
138x^2+162x-11=0
a = 138; b = 162; c = -11;
Δ = b2-4ac
Δ = 1622-4·138·(-11)
Δ = 32316
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{32316}=\sqrt{4*8079}=\sqrt{4}*\sqrt{8079}=2\sqrt{8079}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(162)-2\sqrt{8079}}{2*138}=\frac{-162-2\sqrt{8079}}{276} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(162)+2\sqrt{8079}}{2*138}=\frac{-162+2\sqrt{8079}}{276} $
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