23x+4(x+1)=27(x+1)-23

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Solution for 23x+4(x+1)=27(x+1)-23 equation:


Simplifying
23x + 4(x + 1) = 27(x + 1) + -23

Reorder the terms:
23x + 4(1 + x) = 27(x + 1) + -23
23x + (1 * 4 + x * 4) = 27(x + 1) + -23
23x + (4 + 4x) = 27(x + 1) + -23

Reorder the terms:
4 + 23x + 4x = 27(x + 1) + -23

Combine like terms: 23x + 4x = 27x
4 + 27x = 27(x + 1) + -23

Reorder the terms:
4 + 27x = 27(1 + x) + -23
4 + 27x = (1 * 27 + x * 27) + -23
4 + 27x = (27 + 27x) + -23

Reorder the terms:
4 + 27x = 27 + -23 + 27x

Combine like terms: 27 + -23 = 4
4 + 27x = 4 + 27x

Add '-4' to each side of the equation.
4 + -4 + 27x = 4 + -4 + 27x

Combine like terms: 4 + -4 = 0
0 + 27x = 4 + -4 + 27x
27x = 4 + -4 + 27x

Combine like terms: 4 + -4 = 0
27x = 0 + 27x
27x = 27x

Add '-27x' to each side of the equation.
27x + -27x = 27x + -27x

Combine like terms: 27x + -27x = 0
0 = 27x + -27x

Combine like terms: 27x + -27x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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