23x+lnZ=ln(y+42)

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Solution for 23x+lnZ=ln(y+42) equation:


Simplifying
23x + lnZ = ln(y + 42)

Reorder the terms:
lnZ + 23x = ln(y + 42)

Reorder the terms:
lnZ + 23x = ln(42 + y)
lnZ + 23x = (42 * ln + y * ln)
lnZ + 23x = (42ln + lny)

Solving
lnZ + 23x = 42ln + lny

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Add '-42ln' to each side of the equation.
lnZ + -42ln + 23x = 42ln + -42ln + lny

Reorder the terms:
-42ln + lnZ + 23x = 42ln + -42ln + lny

Combine like terms: 42ln + -42ln = 0
-42ln + lnZ + 23x = 0 + lny
-42ln + lnZ + 23x = lny

Add '-1lny' to each side of the equation.
-42ln + lnZ + -1lny + 23x = lny + -1lny

Combine like terms: lny + -1lny = 0
-42ln + lnZ + -1lny + 23x = 0

Add '-23x' to each side of the equation.
-42ln + lnZ + -1lny + 23x + -23x = 0 + -23x

Combine like terms: 23x + -23x = 0
-42ln + lnZ + -1lny + 0 = 0 + -23x
-42ln + lnZ + -1lny = 0 + -23x
Remove the zero:
-42ln + lnZ + -1lny = -23x

Combine like terms: -23x + 23x = 0
-42ln + lnZ + -1lny + 23x = 0

The solution to this equation could not be determined.

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