23x-18(32x+20)=2(19x+103)

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Solution for 23x-18(32x+20)=2(19x+103) equation: 



23x-18(32x+20)=2(19x+103)

We move all terms to the left:

23x-18(32x+20)-(2(19x+103))=0

We multiply parentheses

23x-576x-(2(19x+103))-360=0



We calculate terms in parentheses: -(2(19x+103)), so:

2(19x+103)

We multiply parentheses

38x+206

Back to the equation:

-(38x+206)



We add all the numbers together, and all the variables

-553x-(38x+206)-360=0

We get rid of parentheses

-553x-38x-206-360=0

We add all the numbers together, and all the variables

-591x-566=0

We move all terms containing x to the left, all other terms to the right

-591x=566

x=566/-591

x=-566/591

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