24(1+3x)+8=7x-28

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Solution for 24(1+3x)+8=7x-28 equation: 



24(1+3x)+8=7x-28

We move all terms to the left:

24(1+3x)+8-(7x-28)=0

We add all the numbers together, and all the variables

24(3x+1)-(7x-28)+8=0

We multiply parentheses

72x-(7x-28)+24+8=0

We get rid of parentheses

72x-7x+28+24+8=0

We add all the numbers together, and all the variables

65x+60=0

We move all terms containing x to the left, all other terms to the right

65x=-60

x=-60/65

x=-12/13

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