24(4u+4)+28u=70(2u+9)

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Solution for 24(4u+4)+28u=70(2u+9) equation: 



24(4u+4)+28u=70(2u+9)

We move all terms to the left:

24(4u+4)+28u-(70(2u+9))=0

We add all the numbers together, and all the variables

28u+24(4u+4)-(70(2u+9))=0

We multiply parentheses

28u+96u-(70(2u+9))+96=0



We calculate terms in parentheses: -(70(2u+9)), so:

70(2u+9)

We multiply parentheses

140u+630

Back to the equation:

-(140u+630)



We add all the numbers together, and all the variables

124u-(140u+630)+96=0

We get rid of parentheses

124u-140u-630+96=0

We add all the numbers together, and all the variables

-16u-534=0

We move all terms containing u to the left, all other terms to the right

-16u=534

u=534/-16

u=-33+3/8

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