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24+2/3(t)=4/3(t-2)
We move all terms to the left:
24+2/3(t)-(4/3(t-2))=0
Domain of the equation: 3t!=0
t!=0/3
t!=0
t∈R
Domain of the equation: 3(t-2))!=0We calculate fractions
t∈R
(6tt/(9t^2t+(-(4*3t)/(9t^2t+24=0
We can not solve this equation
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