24+4(3-x)-2x-3(4x-2)-8=4-6(x-5)-36

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Solution for 24+4(3-x)-2x-3(4x-2)-8=4-6(x-5)-36 equation: 



24+4(3-x)-2x-3(4x-2)-8=4-6(x-5)-36

We move all terms to the left:

24+4(3-x)-2x-3(4x-2)-8-(4-6(x-5)-36)=0

We add all the numbers together, and all the variables

4(-1x+3)-2x-3(4x-2)-(4-6(x-5)-36)+24-8=0

We add all the numbers together, and all the variables

-2x+4(-1x+3)-3(4x-2)-(4-6(x-5)-36)+16=0

We multiply parentheses

-2x-4x-12x-(4-6(x-5)-36)+12+6+16=0



We calculate terms in parentheses: -(4-6(x-5)-36), so:

4-6(x-5)-36

determiningTheFunctionDomain
-6(x-5)+4-36

We add all the numbers together, and all the variables

-6(x-5)-32

We multiply parentheses

-6x+30-32

We add all the numbers together, and all the variables

-6x-2

Back to the equation:

-(-6x-2)



We add all the numbers together, and all the variables

-18x-(-6x-2)+34=0

We get rid of parentheses

-18x+6x+2+34=0

We add all the numbers together, and all the variables

-12x+36=0

We move all terms containing x to the left, all other terms to the right

-12x=-36

x=-36/-12

x=+3

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