24+6(2n-5)=2(n-3)+10n

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Solution for 24+6(2n-5)=2(n-3)+10n equation: 



24+6(2n-5)=2(n-3)+10n

We move all terms to the left:

24+6(2n-5)-(2(n-3)+10n)=0

We multiply parentheses

12n-(2(n-3)+10n)-30+24=0



We calculate terms in parentheses: -(2(n-3)+10n), so:

2(n-3)+10n

We add all the numbers together, and all the variables

10n+2(n-3)

We multiply parentheses

10n+2n-6

We add all the numbers together, and all the variables

12n-6

Back to the equation:

-(12n-6)



We add all the numbers together, and all the variables

12n-(12n-6)-6=0

We get rid of parentheses

12n-12n+6-6=0

We add all the numbers together, and all the variables

=0

n=0/1

n=0

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