24-(1/20)(3x)=16-(1/20)(2x)

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Solution for 24-(1/20)(3x)=16-(1/20)(2x) equation: 



24-(1/20)(3x)=16-(1/20)(2x)

We move all terms to the left:

24-(1/20)(3x)-(16-(1/20)(2x))=0



Domain of the equation: 20)3x!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 20)2x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

-(+1/20)3x-(16-(+1/20)2x)+24=0

We multiply parentheses

-3x^2-(16-(+1/20)2x)+24=0

We multiply all the terms by the denominator


-3x^2*20)2x)-(16-(+24*20)2x)+1=0

We add all the numbers together, and all the variables

-3x^2*20)2x)-(16-4802x)+1=0

Wy multiply elements

-60x^3=0

We do not support expression: x^3

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