24-(r+7)+3=3(r-4)

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Solution for 24-(r+7)+3=3(r-4) equation: 



24-(r+7)+3=3(r-4)

We move all terms to the left:

24-(r+7)+3-(3(r-4))=0

We add all the numbers together, and all the variables

-(r+7)-(3(r-4))+27=0

We get rid of parentheses

-r-(3(r-4))-7+27=0



We calculate terms in parentheses: -(3(r-4)), so:

3(r-4)

We multiply parentheses

3r-12

Back to the equation:

-(3r-12)



We add all the numbers together, and all the variables

-1r-(3r-12)+20=0

We get rid of parentheses

-1r-3r+12+20=0

We add all the numbers together, and all the variables

-4r+32=0

We move all terms containing r to the left, all other terms to the right

-4r=-32

r=-32/-4

r=+8

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