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24-1/2x=1/3x
We move all terms to the left:
24-1/2x-(1/3x)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-1/2x-(+1/3x)+24=0
We get rid of parentheses
-1/2x-1/3x+24=0
We calculate fractions
(-3x)/6x^2+(-2x)/6x^2+24=0
We multiply all the terms by the denominator
(-3x)+(-2x)+24*6x^2=0
Wy multiply elements
144x^2+(-3x)+(-2x)=0
We get rid of parentheses
144x^2-3x-2x=0
We add all the numbers together, and all the variables
144x^2-5x=0
a = 144; b = -5; c = 0;
Δ = b2-4ac
Δ = -52-4·144·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5}{2*144}=\frac{0}{288} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5}{2*144}=\frac{10}{288} =5/144 $
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