24-3z=3(z-2)

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Solution for 24-3z=3(z-2) equation: 



24-3z=3(z-2)

We move all terms to the left:

24-3z-(3(z-2))=0



We calculate terms in parentheses: -(3(z-2)), so:

3(z-2)

We multiply parentheses

3z-6

Back to the equation:

-(3z-6)



We get rid of parentheses

-3z-3z+6+24=0

We add all the numbers together, and all the variables

-6z+30=0

We move all terms containing z to the left, all other terms to the right

-6z=-30

z=-30/-6

z=+5

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