24-9x2+6/3=0

Solution for 24-9x2+6/3=0 equation:

24-9x^2+6/3=0

We add all the numbers together, and all the variables

-9x^2+26=0

a = -9; b = 0; c = +26;
Δ = b2-4ac
Δ = 02-4·(-9)·26
Δ = 936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{936}=\sqrt{36*26}=\sqrt{36}*\sqrt{26}=6\sqrt{26}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{26}}{2*-9}=\frac{0-6\sqrt{26}}{-18}
=-\frac{6\sqrt{26}}{-18}
=-\frac{\sqrt{26}}{-3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{26}}{2*-9}=\frac{0+6\sqrt{26}}{-18}
=\frac{6\sqrt{26}}{-18}
=\frac{\sqrt{26}}{-3}
$