24/(5z+4)=4/(2-1)

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Solution for 24/(5z+4)=4/(2-1) equation: 



24/(5z+4)=4/(2-1)

We move all terms to the left:

24/(5z+4)-(4/(2-1))=0



Domain of the equation: (5z+4)!=0

We move all terms containing z to the left, all other terms to the right

5z!=-4

z!=-4/5

z!=-4/5

z∈R



We add all the numbers together, and all the variables

24/(5z+4)-(4/1)=0

We get rid of parentheses

24/(5z+4)-4/1=0

We calculate fractions

There is no solution for this equation

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