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240=2x(x-2)
We move all terms to the left:
240-(2x(x-2))=0
We calculate terms in parentheses: -(2x(x-2)), so:We get rid of parentheses
2x(x-2)
We multiply parentheses
2x^2-4x
Back to the equation:
-(2x^2-4x)
-2x^2+4x+240=0
a = -2; b = 4; c = +240;
Δ = b2-4ac
Δ = 42-4·(-2)·240
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1936}=44$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-44}{2*-2}=\frac{-48}{-4} =+12 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+44}{2*-2}=\frac{40}{-4} =-10 $
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