240=4(3d+3)+6(3d-2)

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Solution for 240=4(3d+3)+6(3d-2) equation: 



240=4(3d+3)+6(3d-2)

We move all terms to the left:

240-(4(3d+3)+6(3d-2))=0



We calculate terms in parentheses: -(4(3d+3)+6(3d-2)), so:

4(3d+3)+6(3d-2)

We multiply parentheses

12d+18d+12-12

We add all the numbers together, and all the variables

30d

Back to the equation:

-(30d)



We move all terms containing d to the left, all other terms to the right

-30d=-240

d=-240/-30

d=+8

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