240=4(3d+3)+6(3d-2)

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Solution for 240=4(3d+3)+6(3d-2) equation:



240=4(3d+3)+6(3d-2)
We move all terms to the left:
240-(4(3d+3)+6(3d-2))=0
We calculate terms in parentheses: -(4(3d+3)+6(3d-2)), so:
4(3d+3)+6(3d-2)
We multiply parentheses
12d+18d+12-12
We add all the numbers together, and all the variables
30d
Back to the equation:
-(30d)
We move all terms containing d to the left, all other terms to the right
-30d=-240
d=-240/-30
d=+8

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