244=2(3w+18)2w

Solution for 244=2(3w+18)2w equation:

244=2(3w+18)2w

We move all terms to the left:

244-(2(3w+18)2w)=0


We calculate terms in parentheses: -(2(3w+18)2w), so:

2(3w+18)2w

We multiply parentheses

12w^2+72w

Back to the equation:

-(12w^2+72w)


We get rid of parentheses

-12w^2-72w+244=0

a = -12; b = -72; c = +244;
Δ = b2-4ac
Δ = -722-4·(-12)·244
Δ = 16896
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{16896}=\sqrt{256*66}=\sqrt{256}*\sqrt{66}=16\sqrt{66}$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-72)-16\sqrt{66}}{2*-12}=\frac{72-16\sqrt{66}}{-24}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-72)+16\sqrt{66}}{2*-12}=\frac{72+16\sqrt{66}}{-24}
$