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244=2(w+35)2w
We move all terms to the left:
244-(2(w+35)2w)=0
We calculate terms in parentheses: -(2(w+35)2w), so:We get rid of parentheses
2(w+35)2w
We multiply parentheses
4w^2+140w
Back to the equation:
-(4w^2+140w)
-4w^2-140w+244=0
a = -4; b = -140; c = +244;
Δ = b2-4ac
Δ = -1402-4·(-4)·244
Δ = 23504
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{23504}=\sqrt{16*1469}=\sqrt{16}*\sqrt{1469}=4\sqrt{1469}$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-140)-4\sqrt{1469}}{2*-4}=\frac{140-4\sqrt{1469}}{-8} $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-140)+4\sqrt{1469}}{2*-4}=\frac{140+4\sqrt{1469}}{-8} $
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