244=2(w+35)2w

Solution for 244=2(w+35)2w equation:

244=2(w+35)2w

We move all terms to the left:

244-(2(w+35)2w)=0


We calculate terms in parentheses: -(2(w+35)2w), so:

2(w+35)2w

We multiply parentheses

4w^2+140w

Back to the equation:

-(4w^2+140w)


We get rid of parentheses

-4w^2-140w+244=0

a = -4; b = -140; c = +244;
Δ = b2-4ac
Δ = -1402-4·(-4)·244
Δ = 23504
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{23504}=\sqrt{16*1469}=\sqrt{16}*\sqrt{1469}=4\sqrt{1469}$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-140)-4\sqrt{1469}}{2*-4}=\frac{140-4\sqrt{1469}}{-8}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-140)+4\sqrt{1469}}{2*-4}=\frac{140+4\sqrt{1469}}{-8}
$