245-9b/8b=5b

Solution for 245-9b/8b=5b equation:

245-9b/8b=5b

We move all terms to the left:

245-9b/8b-(5b)=0


Domain of the equation: 8b!=0

b!=0/8

b!=0

b∈R


We add all the numbers together, and all the variables

-5b-9b/8b+245=0

We multiply all the terms by the denominator


-5b*8b-9b+245*8b=0

We add all the numbers together, and all the variables

-9b-5b*8b+245*8b=0

Wy multiply elements

-40b^2-9b+1960b=0

We add all the numbers together, and all the variables

-40b^2+1951b=0

a = -40; b = 1951; c = 0;
Δ = b2-4ac
Δ = 19512-4·(-40)·0
Δ = 3806401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3806401}=1951$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1951)-1951}{2*-40}=\frac{-3902}{-80}
=48+31/40
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1951)+1951}{2*-40}=\frac{0}{-80}
=0
$