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24=-3(2a-15)a
We move all terms to the left:
24-(-3(2a-15)a)=0
We calculate terms in parentheses: -(-3(2a-15)a), so:We get rid of parentheses
-3(2a-15)a
We multiply parentheses
-6a^2+45a
Back to the equation:
-(-6a^2+45a)
6a^2-45a+24=0
a = 6; b = -45; c = +24;
Δ = b2-4ac
Δ = -452-4·6·24
Δ = 1449
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1449}=\sqrt{9*161}=\sqrt{9}*\sqrt{161}=3\sqrt{161}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-3\sqrt{161}}{2*6}=\frac{45-3\sqrt{161}}{12} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+3\sqrt{161}}{2*6}=\frac{45+3\sqrt{161}}{12} $
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