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24=10x+12/x
We move all terms to the left:
24-(10x+12/x)=0
Domain of the equation: x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-(+10x+12/x)+24=0
We get rid of parentheses
-10x-12/x+24=0
We multiply all the terms by the denominator
-10x*x+24*x-12=0
We add all the numbers together, and all the variables
24x-10x*x-12=0
Wy multiply elements
-10x^2+24x-12=0
a = -10; b = 24; c = -12;
Δ = b2-4ac
Δ = 242-4·(-10)·(-12)
Δ = 96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{96}=\sqrt{16*6}=\sqrt{16}*\sqrt{6}=4\sqrt{6}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-4\sqrt{6}}{2*-10}=\frac{-24-4\sqrt{6}}{-20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+4\sqrt{6}}{2*-10}=\frac{-24+4\sqrt{6}}{-20} $
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