24=16.t2+40

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Solution for 24=16.t2+40 equation: 



24=16.t^2+40

We move all terms to the left:

24-(16.t^2+40)=0

We get rid of parentheses

-16.t^2-40+24=0

We add all the numbers together, and all the variables

-16t^2-16=0

a = -16; b = 0; c = -16;
Δ = b2-4ac
Δ = 02-4·(-16)·(-16)
Δ = -1024
Delta is less than zero, so there is no solution for the equation

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