24=2(1+1/4l)+2l

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Solution for 24=2(1+1/4l)+2l equation: 



24=2(1+1/4l)+2l

We move all terms to the left:

24-(2(1+1/4l)+2l)=0



Domain of the equation: 4l)+2l)!=0

l!=0/1

l!=0

l∈R



We add all the numbers together, and all the variables

-(2(1/4l+1)+2l)+24=0

We multiply all the terms by the denominator


-(2(1+24*4l+1)+2l)=0



We calculate terms in parentheses: -(2(1+24*4l+1)+2l), so:

2(1+24*4l+1)+2l

We add all the numbers together, and all the variables

2(24*4l+2)+2l

We add all the numbers together, and all the variables

2l+2(24*4l+2)

We multiply parentheses

2l+192l+4

We add all the numbers together, and all the variables

194l+4

Back to the equation:

-(194l+4)



We get rid of parentheses

-194l-4=0

We move all terms containing l to the left, all other terms to the right

-194l=4

l=4/-194

l=-2/97

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