24=2w*w*3

Solution for 24=2w*w*3 equation:

24=2w*w*3

We move all terms to the left:

24-(2w*w*3)=0

We add all the numbers together, and all the variables

-(+2w*w*3)+24=0

We get rid of parentheses

-2w*w*3+24=0

Wy multiply elements

-6w^2*3+24=0

Wy multiply elements

-18w^2+24=0

a = -18; b = 0; c = +24;
Δ = b2-4ac
Δ = 02-4·(-18)·24
Δ = 1728
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1728}=\sqrt{576*3}=\sqrt{576}*\sqrt{3}=24\sqrt{3}$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24\sqrt{3}}{2*-18}=\frac{0-24\sqrt{3}}{-36}
=-\frac{24\sqrt{3}}{-36}
=-\frac{2\sqrt{3}}{-3}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24\sqrt{3}}{2*-18}=\frac{0+24\sqrt{3}}{-36}
=\frac{24\sqrt{3}}{-36}
=\frac{2\sqrt{3}}{-3}
$