24=3(m+4)+m

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Solution for 24=3(m+4)+m equation: 



24=3(m+4)+m

We move all terms to the left:

24-(3(m+4)+m)=0



We calculate terms in parentheses: -(3(m+4)+m), so:

3(m+4)+m

We add all the numbers together, and all the variables

m+3(m+4)

We multiply parentheses

m+3m+12

We add all the numbers together, and all the variables

4m+12

Back to the equation:

-(4m+12)



We get rid of parentheses

-4m-12+24=0

We add all the numbers together, and all the variables

-4m+12=0

We move all terms containing m to the left, all other terms to the right

-4m=-12

m=-12/-4

m=+3

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