24b2=96b

Solution for 24b2=96b equation:

24b^2=96b

We move all terms to the left:

24b^2-(96b)=0

a = 24; b = -96; c = 0;
Δ = b2-4ac
Δ = -962-4·24·0
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9216}=96$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-96)-96}{2*24}=\frac{0}{48}
=0
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-96)+96}{2*24}=\frac{192}{48}
=4
$