24x+(7x(1/2))=660

Solution for 24x+(7x(1/2))=660 equation:

24x+(7x(1/2))=660

We move all terms to the left:

24x+(7x(1/2))-(660)=0

We add all the numbers together, and all the variables

24x+(7x(+1/2))-660=0

We multiply all the terms by the denominator


24x*2))+(7x(+1-660*2))=0

We add all the numbers together, and all the variables

24x*2))+(7x(-1319))=0

We add all the numbers together, and all the variables

24x*2))+(7x(=0

Wy multiply elements

48x^2=0

a = 48; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·48·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{96}=0$