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24x-(5-3x)=2(x+5)
We move all terms to the left:
24x-(5-3x)-(2(x+5))=0
We add all the numbers together, and all the variables
24x-(-3x+5)-(2(x+5))=0
We get rid of parentheses
24x+3x-(2(x+5))-5=0
We calculate terms in parentheses: -(2(x+5)), so:We add all the numbers together, and all the variables
2(x+5)
We multiply parentheses
2x+10
Back to the equation:
-(2x+10)
27x-(2x+10)-5=0
We get rid of parentheses
27x-2x-10-5=0
We add all the numbers together, and all the variables
25x-15=0
We move all terms containing x to the left, all other terms to the right
25x=15
x=15/25
x=3/5
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