24x2+38x+15=0

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Solution for 24x2+38x+15=0 equation:



24x^2+38x+15=0
a = 24; b = 38; c = +15;
Δ = b2-4ac
Δ = 382-4·24·15
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(38)-2}{2*24}=\frac{-40}{48} =-5/6 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(38)+2}{2*24}=\frac{-36}{48} =-3/4 $

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