24x2-47x+20=0

Solution for 24x2-47x+20=0 equation:

24x^2-47x+20=0

a = 24; b = -47; c = +20;
Δ = b2-4ac
Δ = -472-4·24·20
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-47)-17}{2*24}=\frac{30}{48}
=5/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-47)+17}{2*24}=\frac{64}{48}
=1+1/3
$