24y+3y-4=32y-12

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Solution for 24y+3y-4=32y-12 equation: 



24y+3y-4=32y-12

We move all terms to the left:

24y+3y-4-(32y-12)=0

We add all the numbers together, and all the variables

27y-(32y-12)-4=0

We get rid of parentheses

27y-32y+12-4=0

We add all the numbers together, and all the variables

-5y+8=0

We move all terms containing y to the left, all other terms to the right

-5y=-8

y=-8/-5

y=1+3/5

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