24y+6=4(6y+3/2)

Solution for 24y+6=4(6y+3/2) equation:

24y+6=4(6y+3/2)

We move all terms to the left:

24y+6-(4(6y+3/2))=0

We add all the numbers together, and all the variables

24y-(4(+6y+3/2))+6=0

We multiply all the terms by the denominator


24y*2))-(4(+6y+3+6*2))=0

We add all the numbers together, and all the variables

24y*2))-(4(6y+15))=0

We add all the numbers together, and all the variables

24y*2))-(4(6y=0

Wy multiply elements

48y^2=0

a = 48; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·48·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{96}=0$