24y2+58y+28=0

Solution for 24y2+58y+28=0 equation:

24y^2+58y+28=0

a = 24; b = 58; c = +28;
Δ = b2-4ac
Δ = 582-4·24·28
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(58)-26}{2*24}=\frac{-84}{48}
=-1+3/4
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(58)+26}{2*24}=\frac{-32}{48}
=-2/3
$