25(3b+3+1+2)=30(15b)

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Solution for 25(3b+3+1+2)=30(15b) equation: 



25(3b+3+1+2)=30(15b)

We move all terms to the left:

25(3b+3+1+2)-(30(15b))=0

determiningTheFunctionDomain
25(3b+3+1+2)-3015b=0

We add all the numbers together, and all the variables

25(3b+6)-3015b=0

We add all the numbers together, and all the variables

-3015b+25(3b+6)=0

We multiply parentheses

-3015b+75b+150=0

We add all the numbers together, and all the variables

-2940b+150=0

We move all terms containing b to the left, all other terms to the right

-2940b=-150

b=-150/-2940

b=5/98

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