25(3b+3+1+2)=30(15b)

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Solution for 25(3b+3+1+2)=30(15b) equation:



25(3b+3+1+2)=30(15b)
We move all terms to the left:
25(3b+3+1+2)-(30(15b))=0
determiningTheFunctionDomain 25(3b+3+1+2)-3015b=0
We add all the numbers together, and all the variables
25(3b+6)-3015b=0
We add all the numbers together, and all the variables
-3015b+25(3b+6)=0
We multiply parentheses
-3015b+75b+150=0
We add all the numbers together, and all the variables
-2940b+150=0
We move all terms containing b to the left, all other terms to the right
-2940b=-150
b=-150/-2940
b=5/98

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