25(4y+5)=-50(-y-1)

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Solution for 25(4y+5)=-50(-y-1) equation: 



25(4y+5)=-50(-y-1)

We move all terms to the left:

25(4y+5)-(-50(-y-1))=0

We add all the numbers together, and all the variables

25(4y+5)-(-50(-1y-1))=0

We multiply parentheses

100y-(-50(-1y-1))+125=0



We calculate terms in parentheses: -(-50(-1y-1)), so:

-50(-1y-1)

We multiply parentheses

50y+50

Back to the equation:

-(50y+50)



We get rid of parentheses

100y-50y-50+125=0

We add all the numbers together, and all the variables

50y+75=0

We move all terms containing y to the left, all other terms to the right

50y=-75

y=-75/50

y=-1+1/2

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